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4=4x^2+6x
We move all terms to the left:
4-(4x^2+6x)=0
We get rid of parentheses
-4x^2-6x+4=0
a = -4; b = -6; c = +4;
Δ = b2-4ac
Δ = -62-4·(-4)·4
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-10}{2*-4}=\frac{-4}{-8} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+10}{2*-4}=\frac{16}{-8} =-2 $
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